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Thread: Lowering the crossover point.

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  1. #1
    Senior Hostboard Member aditya's Avatar
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    Re: Lowering the crossover point.

    Quote Originally Posted by cradeldorf View Post
    I was not aware of that. Is that because your calling the DCR the ohm resistance? I didn't think they are the same? Because measuring DCR and measuring ohms seem like two different processes when I read up on testing inductors it wasn't a simple measurement like a DCR measurement is?. I was calculating them using the 16 ohm rating.
    The 16 ohm thing is called as the impedance, which is DCR+reactance. DCR is constant, but reactance varies with frequency, and as a result impedance varies. To calculate xover component values at a particular 'f' one has to know the impedance at that 'f'. The specified impedance (ohms value as you have said) for a driver generally means it to be valid at 1KHz. At other freq it will be different, even may become the same as the DCR. So here comes the 'impedance-graph'. Now just b'coz the graph is in hand does not mean that the computed values will be the workable ones. This is so b'coz, as the graphs are not straight lines, the resultant filter response slopes will be far from what what was calculated. So now comes the difficult part, that is to adjust the values of the components, type of the filters, choice of xover-'f' etc., so that it can deliver the goods.
    Last edited by aditya; August 16th, 2012 at 07:41 AM.

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    Lowering the crossover point.


    Alien_Shore's Avatar
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    Re: Lowering the crossover point.

    Quote Originally Posted by cradeldorf View Post
    I'm never touching them again.
    hahaha ok, if you say so!
    - Mike

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    Lowering the crossover point.


    Alien_Shore's Avatar
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    Re: Lowering the crossover point.

    35422-SMARTYPANTS.jpg
    OK Let us know how they sound!
    - Mike

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